I was always befuddled by Permutations & Combinations in Maths, so would someone (bplus, I guess!) show where I have gone wrong?

:D 52! permutations of ways a deck can be ordered, yet only one combination of 4 aces, 4 kings... 4 2's.

level 1

Who_GNU

1 point

·

5 years ago

To be exact, 52! equals 80,658,175,170,943,878,571,660,636,856,403,766,975,289,505,440,883,277,824,000,000,000,000

8x10^67

How many hands of 13 from a deck?

EDIT: formula for Combination = N!/(R! * (N-R)!)

52! / (39! * 13!) OK Pete, time to test your string math! ;-))

Only 4 or those hands can have 4 Aces, 4 Kings, 4 Queens, and 1 of 4 Jacks

APPEND: Oh Hey! It's right in your link Qwerky!

The total number of possible 13 card hands is: COMBIN(52,13) = 635,013,559,600

So I was right 4/635,013,559,600

APPEND #2: I had wrong formula for combination originally. _integer64 might be able to handle the calculation.